SOLVED: For a gas at a given temperature, the compression factor
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VIDEO ANSWER: Hello students: let's look at the question: l n, that integrate integration and 0 z minus 1 bracket, close d p by p here. Minus 1 is equal to minus 8.50 into 10 to the power minus 3 p by p, not plus 3.50 into 10. To the power minus 9. P
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SOLVED: A gas at 350 K and 12 atm has a molar volume 12 per cent
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